Вычислите:
а) \(6\frac{1}{3} - 8 = -(8 - 6\frac{1}{3}) = -(7\frac{3}{3} - 6\frac{1}{3}) = -1\frac{2}{3}\);

б) \( -2\frac{2}{7} + 4\frac{3}{5} = 4\frac{3}{5} - 2\frac{2}{7} = 4\frac{21}{35} - 2\frac{10}{35} = 2\frac{11}{35}\);

в) \(5\frac{1}{3} - 6\frac{1}{4} = -(6\frac{1}{4} - 5\frac{1}{3}) = -(6\frac{3}{12} - 5\frac{4}{12}) = -(5\frac{15}{12} - 5\frac{4}{12}) = -\frac{11}{12}\);

г) \(\frac{3}{8} : (-\frac{9}{16}) = -(\frac{3}{8} : \frac{9}{16}) = -(\frac{3}{8} \cdot \frac{16}{9}) = \frac{3 \cdot 16}{8 \cdot 9} = \frac{1 \cdot 2}{1 \cdot 3} = \frac{2}{3}\);

д) \(\frac{5}{12} \cdot (-6) = -(\frac{5}{12} \cdot 6) = -(\frac{5}{2} \cdot 1) = -2\frac{1}{2} = -2,5\);

е) \(-3\frac{2}{9} \cdot 3 = -(\frac{29}{9} \cdot 3) = -(\frac{29}{3} \cdot 1) = -9\frac{2}{3} \);

ж) \(\frac{4}{7} \cdot (-49) = -(\frac{4}{7} \cdot 49) = -(\frac{4}{1} \cdot 7) = -\frac{28}{1} = -28\);

з) \(-16 : (-\frac{4}{9}) = --(16 : \frac{4}{9}) = 16 \cdot \frac{9}{4} = 4 \cdot 9 = 36\);

и) \(-3\frac{1}{2} \cdot (-1\frac{3}{7}) = --(3\frac{1}{2} \cdot 1\frac{3}{7}) = \frac{7}{2} \cdot \frac{10}{7} = \frac{7 \cdot 10}{2 \cdot 7} = \frac{1 \cdot 5}{1 \cdot 1} = 5\).